Biology, asked by pratham495630, 8 months ago

Oxidation number of Ni in Ka[ni (CN).]​

Answers

Answered by SpM1014lover
0

Answer:

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Explanation:

  1. ️‍️️‍️️‍️
Answered by Anonymous
4

Answer:

hey mate right answer is here.

Explanation:

it is -1.

The Oxidation number of Ni in [Ni(CN)4]2− [ N i ( C N ) 4 ] 2 − . Let the oxidation number of Ni be x. The oxidation number of Cyanide, CN is -1.

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