Oxidation number of Ni in Ka[ni (CN).]
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- ️️️️️️
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hey mate right answer is here.
Explanation:
it is -1.
The Oxidation number of Ni in [Ni(CN)4]2− [ N i ( C N ) 4 ] 2 − . Let the oxidation number of Ni be x. The oxidation number of Cyanide, CN is -1.
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