Question

oxidation number of Ni In [Ni(CN)4]4-​

Answer 1

Answer:

oxidation number of Ni is 0

Explanation:

let Ni=x,CN=-4,

x(Ni)+4(CN)=-4

x+4×(-1)=-4

x-4=-4

x=-4+4

x=0

Answer 2

The question is incomplete, here is the complete question:

What is the oxidation number of Ni in [Ni(CN)₄]²⁻?

Options: 0, +1, +4, +3, +2

The oxidation state of nickel in the given complex is +2

Explanation:

A coordination complex contains ligands that are bonded to the central metal atom or ion to form coordinate covalent bond. The ligands and the central metal together form the coordination sphere.

The given coordination complex is:  $[Ni(CN)_4]^{4-}$

Central metal atom is Nickel (Ni)

Coordination sphere consists of 4 cyanide ligands that carry -1 charge. The coordination sphere carries -4 charge.

Let the oxidation state of Ni be 'x'

Oxidation state of $CN^-$ ligands = -1

Evaluating the oxidation state of nickel, we get:

$\Rightarrow x+4(-1)=-2\\\\\Rightarrow x=+2$

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