Question

oxidation number of nitrogen in nano2

Answer 1

Oxidation number of
Na = +1
Oxygen = -2
Nitrogen = x

There is no charge on the compound. Hence sum of all oxidation numbers is zero.

+1 + x + 2(-2) = 0
x = +3

Oxidation number of Nitrogen in NaNO2 is +3

Answer 2

Answer:

The oxidation number of Nitrogen in $\bold{\mathrm{NaNO}_{2}}$ is 3.

This is because the If we consider the elements individually, then:

The oxidation number of Na (sodium) = +1

The oxidation number of $\bigcirc_{2}$ (oxygen) = -2

And the overall charge on the compound = 0.

Therefore, let the oxidation number of Na = x

1 + x -2(2) = 0

x – 3 = 0

x = 3