Question

Oxidation number of p in na2h2po2

Answer 1

Answer:

oxidation number of p in na2h2po2 is 2.

Answer 2

Oxidation number of $P$  in $\[N{{a}_{2}}{{H}_{2}}P{{O}_{2}}\]$  is zero.

Explanation:

• We are asked to find the oxidation stae of phosphorous in $\[N{{a}_{2}}{{H}_{2}}P{{O}_{2}}\]$

• Phosphorous is present in nitrogen family.

• The other atoms present in the compound are sodium atom which is an alkali metal,hydrogen and oxygen.

• Let us consider the total charge on the compound be zero.
• The oxidation number of hydrogen is considered as $+1$ and oxygen as $-2$.

• Then,$2+2+x-4=0$ where 'x' is the oxidation number of phosphorous.
• Solving for'x', we get $x=0$.