Question

oxidation number of p in NaH²pO²​

Answer 1

Answer:

NaH2PO2 be x

os of oxygen is -2

os of Na is +1

os of hydrogen is +1

Total os of a molecule is zero (if neutral).

so by adding  os we get

(+1)+(+1×2)+(x)+-2×2)=0

or

x=+1

So oxidation state of phosphorus in NaH2PO2 is +1

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Answer 2

Answer:

oxidation no. of phosphorus is=+1