Question

Oxidation number of S in Na2S2 is -
( a ) + 1
(b) - 2
(c)-1
(d)o

Answer 1

Answer:

oxidation number of s is -1

Explanation:

Na2S2 = 0 bcz no charge on compound

let oxidation number of sulphur be x

+2+2x = 0

x= -1

Answer 2

Answer:

-1

Explanation:

2(+1)+2x=0

x=-1

Hope it's helpful