Question

Oxidation number of s in so4--

Answer 1

oxidation number of s is 6

Answer 2

Answer:

Oxidation number of S in $SO_{4}$²⁻ is 6

Oxidation number is also called Oxidation state . It is the total number of electrons which are loose or gain by the atom to form a bond with the another atom. It is the degree of oxidation. The sum of oxidation numbers in a neutral compound is zero.

The valency of oxygen is 2 because outermost orbit contains 6 electrons so valency = 6-8= -2

In $SO_{4}$²⁻  it has 2 negative charge also,

So, let us suppose Oxidation number of S be x,

x + 4×(-2) = -2

x = -2+8

x= +6