oxidation number of sulphur in
KAl(SO2)4.12H2O
nicky1908:
but can someone explain that after (SO2)4 there is a dot and then H2O so why we have do we have to add not multiply
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3 is the oxidation number of sulphur in given compound as
+1+3+4x-2*2*4+24-24=0
+4+4x-16=0
+4x=12
x=+3
+1+3+4x-2*2*4+24-24=0
+4+4x-16=0
+4x=12
x=+3
so what does that dot represents
thank you
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