Question

oxidation number of V2O7^-4​

Answer 1

Answer:

Oxidation of V = +5 & V2 = +10

Explanation:

2x + 7×(-2) = -4

2x = -4 + 14

x = 10 ÷ 2

x = 5

Answer 2

Answer:

The oxidation number of vanadium is +5 and the oxidation number of oxygen is -2.

Explanation:

We have to find the oxidation number of V₂O₇⁴⁻.

Consider that the oxidation state of the Vanadium is x. We know that the oxidation state of oxygen is -2.

$2x + 7(-2) = -4$

$2x -14 =-4$

$2x = 14-4$

$2x = 10$

$x = +5$

Therefore, the oxidation number of vanadium in V₂O₇⁴⁻ is +5.

Oxidation number:-

• The oxidation number is a charge of an atom or define  oxidation level of an atom in a chemical compound.

• The oxidation number can be represented by using integrals like zero, positive or negative.

• Oxidation number represents of electron quantity lost or gained by an atom of a specific element in a chemical bond with atom of another element.

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