Question

Oxidation numbers of iodine in IPo4

Answer 1

Explanation:

oxidation state of iodine be x.

x-3=0, x=+3x−3=0,x=+3,

\because PO^{3-}_4∵PO

4

3−

has combined oxidation number -3−3.

\therefore x-3=0∴x−3=0

\therefore x=+3∴x=+3

Thus oxidation state of iodine is +3.