Question

Oxidation numbers of p in HPO4 2-​

Answer 1

H -1

O - -2 x 4

P + 1 + -8 = -2

oxidation state of P is +5

Answer 2

Answer: Oxidation state of P is +5.

Explanation:

Rules for Oxidation Numbers :

The oxidation number of a free element is always zero.

The oxidation number of a monatomic ion equals the charge of the ion.

The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.

The oxidation number of  oxygen (O)  in compounds is usually -2, but it is -1 in peroxides.

The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

The given coordination compound is, $HPO_4^{2-}$

Let the oxidation state of P be, 'x'

$1(+1)+1(x)+4(-2)=-2$

$x=+5$

Hence, the oxidation state of P is +5.