Question

Oxidation state for hg in hg[co(scn)4] is

Answer 1

Here's your answer!

$> \: </strong><strong>L</strong><strong>et \: oxidation \: state \: of \: mercury \: be \: x$

$> \: </strong><strong>O</strong><strong>xidation \: state \: of \: cobalt \: = \: + 3$

$> \: </strong><strong>O</strong><strong>xidation \: state \: of \: thiocyanate \: ion \: = \: - 1$

> So, x + 3 + 4 (-1) = 0

> x + 3 - 4 = 0

> x - 1 = 0

> x = 1

Oxidation state of Mercury is +1.

Hope it helps!