Oxidation state of N in (NH4)2 SO2
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Answered by
1
Answer:
Hence, the O.N. of N in (NH4)²SO4 is -3.
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Answered by
0
Explanation:
(NH
4
)
2
SO
4
⇌2NH
4
+
+SO
4
2−
N
∗
H
4
+
Let, x be the oxidation state of N.
x+4×1=+1; ⇒x=−3
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