Oxidation state of nickel in [Ni(NH3)6](BF4) 2
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Oxidation state is a 0 [Ni(NH3)6]BF4)2 in this let Oxidation state of nickel be x and then x +6(0)-2(0) =0 since NH3 AND BF4 have oxidation number (0) so x . 0Oxidation state of Ni is zero.
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