Oxidation state of nitrogen in H-N = C is
(1) - 4
(3) -3
(2) + 3
(4) -2
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You use the rules for oxidation numbers to calculate that the oxidation number of
N
is +5.
Explanation:
The important rules here are:
The oxidation number of oxygen in a compound is usually -2, except in peroxides, where it is -1.
The sum of all the oxidation numbers in a polyatomic ion is equal to the charge on the ion.
The formula of nitrate ion is
NO
-
3
.
Rule 1 tells us that the oxidation number of
O
is -2:
[
N
-2
O
3
]
-
.
The three
O
atoms have a total oxidation number of -6.
Rule 2 tells us that the sum of all the oxidation numbers equals the charge on the ion.
Let
x
= the oxidation number of
N
.
x
+
(
-6
)
=
-1
x
=
-1
−
(-6)
=
-1 + 6
=
+
5
∴ The oxidation number of
N
is +5:
[
+5
N
-2
O
3
]
-
.
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