Oxidation state of p in h2po-4
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In the case of H2PO4- the overall charge is -1 thus your individual oxidation numbers must add up to -1. H is normally +1 and O is normally -2( I say normally because there is always an exception). Applying this to H2PO4- we get… So just from our H and O we get an overall of -6 while needing final to be -1.
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Explanation:
In the case of H2PO4- the overall charge is -1 thus your individual oxidation numbers must add up to -1. H is normally +1 and O is normally -2( I say normally because there is always an exception). Applying this to H2PO4- we get… So just from our H and O we get an overall of -6 while needing final to be -1
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