Question

OXIDATION STATE OF P IN H4P2O5.H4P2O6.H4P2O7 ARE

Answer 1

(+1)4+2X+(-2)5=0;X=+2
(+1)4+2X+(-2)6=0;X=+4
(+1)4+2X+(-2)7=0;X=+5

Answer 2

H₄P₂O₅ = 4 + 2X -10 = 0 => -6 + 2X = 0 => 2X = 6 => X = 3

H₄P₂O₆ = 4 + 2X -12 = 0 => 2X - 8 = 0 => 2X = 8 => X = 4

H₄P₂O₇ = 4 + 2X -14 = 0 => 2X - 10 = 0 => 2X = 10 => X = 5