Question

oxidation state of 'S' in sulphuric acid and peroxomonosulphuric acid respectively are
(A)VI and IV
(B)VI and V
(C)VI and VI
(D)IV and VI​

Answer 1

Answer:

(C)VI and VI is the right answer

Explanation:

(i) Sulphuric acid (H₂SO₄)

=> Assuming O.S. of S is x    [OS is the oxidation state]

=> 2(+1) + x + 4(-2) = 0     [H = +1; O = -2]

=> x = 8 -2

=> x = 6 or (VI)

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(ii) Peroxomonosulphuric acid (H₂SO₅)

=> Assuming O.S. of S is y  

[Note : peroxomonosulphuric acid has a peroxy bond linked between 2 oxygen atoms. Their OS is -1, not -2]

[H = +1, 3 O's(normal) = -2; 2O's(peroxy) = -1]

=> 2(1) + y + 2(-1) + 3(-2) = 0

=> 2 + y -2 -6 = 0

=> y = 6 or (VI)

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❖ Extra information

⟡ Peroxomonosulphuric acid is also called Caro's acid

⟡ The structures of Sulphuric acid (H₂SO₄) and peroxomonosulphuric acid (H₂SO₅) are given in the attachment

Hope it helps!!

Answer 2

Answer:

(C)VI and VI

Explanation:

hope it will help you