oxidation state of sulpher in suphide and sulphate are respectively how many?
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Sulphide is S²⁻
There is a charge and oxidation number of '-2' on sulphur
whereas;
Sulphate is SO₄²⁻
For calculating oxidation state; consider it as x
Now; x + (-2×4) = -2
x = +8-2
x = +6
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