Chemistry, asked by Afiya2164, 11 months ago

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below:
\frac{1}{2} Cl_2 (g) \xrightarrow []{\frac{1}{2}\Delta_{diss}H^{\otimes}} Cl(g) \xrightarrow []{\Delta_{eg}H^{\otimes}} Cl^-(g) \xrightarrow []{\Delta_{Hyd}H^{\otimes}} Cl^-(aq)
(using the data, \Delta_{diss}H^{\ominus}_{Cl_2}= 240 kJ mol⁻¹, \Delta_{eg}H^{\ominus}_{Cl} = –349 kJ mol⁻¹, \Delta_{hyd}H^{\ominus}_{Cl} = –381 kJ mol⁻¹), will be
(a) + 152 kJ mol⁻¹
(b) – 610 kJ mol⁻¹
(c) – 850 kJ mol⁻¹
(d) + 120 kJ mol⁻¹

Answers

Answered by Bevin234
0

(d) +120kj mol-1..............

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