Question

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below:
$\frac{1}{2} Cl_2(g) \xrightarrow[]{\frac{1}{2} \Delta_{diss} H^{\ominus}} Cl(g) \xrightarrow[]{\Delta_{eg} H^{\ominus}} Cl^- (g) \xrightarrow[]{\Delta_{Hyd} H^{\ominus}} Cl^- (aq)$
(using the data, $\Delta_{diss} H^{\ominus}_{Cl_2}$ = 240 kJ mol⁻¹, $\Delta_{eg} H^{\ominus}_{Cl}$ = –349 kJ mol⁻¹, $\Delta_{Hyd} H^{\ominus} _{Cl}$ = –381 kJ mol⁻¹), will be
(a) + 152 kJ mol⁻¹
(b) – 610 kJ mol⁻¹
(c) – 850 kJ mol⁻¹
(d) + 120 kJ mol⁻¹

Answer 1

1/2 cl2 ke dissociation ke liye enrgy 240/2 required hogi means +120kj/mol and first electron affinity is normally exothermic then -349kj/mol and hydration energy is exothermic then -381 then total energy is +120-349-381 = -610 kj/mol

Answer 2

Explanation:

The correct answer is option (b)

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