Oxygen exhibit -1 oxidation state in:(a) OF₂(b) H₂O₂(c) HClO(d) H₂O
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Answered by
1
Hi , friend !!!
here is your answer !!!
OF2 ==> x + (-2) = 0
x = -2
b ) H2O2
=> 2×1 + 2x = 0
x = -1
c ) HClO =>
1 + (-1) + x = 0
x = 0
d ) H20
2 + x = 0
x = -2
clearly we can see that. H2O2 have oxidation State of Oxygen is -1
hope it helps you
thanks !!
here is your answer !!!
OF2 ==> x + (-2) = 0
x = -2
b ) H2O2
=> 2×1 + 2x = 0
x = -1
c ) HClO =>
1 + (-1) + x = 0
x = 0
d ) H20
2 + x = 0
x = -2
clearly we can see that. H2O2 have oxidation State of Oxygen is -1
hope it helps you
thanks !!
Answered by
2
Option B is correct.......H2O2
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