P(1,-2) is a point on the line segment A(3,-6) and B(x,y) such that AP:PB is equal to 2:3. find the coordinates of B.
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sameer236:
Yes
send me thn
First two coordinate given a and b and a point p
Its divided in 2 ratio 3
I use section formulae
tht formula u send me
And put x is 1 and y is -2 and solve
Hmm
sr its getting me difficult better send me pic itself
i forgotten the way of method
Answered by
15
point P divides line segment in ratio 2:3
P(1,-2) , A(3,-6), and B(X,Y)
M1 = 2 ,M2 = 3, X1 = 3 ,X2 = X, Y1 = -6 , Y2 = Y
P( M1X2+M2X1/M1+M2) , (M1Y2+M2Y1/M1+M2)
P(2×X+3×3/2+3), (2×Y+3(-6)/2+3)
P(2X+9/5) , (2Y-18/5)
But the points of P are(1,-2)
2X+9/5 = 1, 2Y-18/5 = -2
Solve this u will get your answer
P(1,-2) , A(3,-6), and B(X,Y)
M1 = 2 ,M2 = 3, X1 = 3 ,X2 = X, Y1 = -6 , Y2 = Y
P( M1X2+M2X1/M1+M2) , (M1Y2+M2Y1/M1+M2)
P(2×X+3×3/2+3), (2×Y+3(-6)/2+3)
P(2X+9/5) , (2Y-18/5)
But the points of P are(1,-2)
2X+9/5 = 1, 2Y-18/5 = -2
Solve this u will get your answer
I message u
I send u fully pic
Of that question becoz I solved it
ok sr thnk u
now get it
the answer
Ok
thnk u saniya nd sameer sr
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