Question

(p+1)-(2p+4)/
3-5p=1/23,find p.
​

Answer 1

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Answer 2

Given:

• $\sf \: Equation: \: \displaystyle{\sf\:\dfrac{(\:p\:+\:1\:)\:-\:(\:2p\:+\:4\:)}{3\:-\:5p}\:=\:\dfrac{1}{23}}$

To find:

• The value of p

Solution:

$\begin{gathered}\displaystyle{\sf: \implies\dfrac{(\:p\:+\:1\:)\:-\:(\:2p\:+\:4\:)}{3\:-\:5p}\:=\:\dfrac{1}{23}} \\ \\ \\ \displaystyle{:\implies\sf\:\dfrac {p\:+\:1\:-\:2p\:-\:4}{3\:-\:5p}\:=\:\dfrac{1}{23}} \\ \\ \\ \displaystyle{:\implies\sf\:23\:(\:p\:-\:2p\:+\:1\:-\:4\:)\:=\:3\:-\:5p} \\ \\ \\ \displaystyle{:\implies\sf\:23\:(\:-\:p\:-\:3\:)\:=\:3\:-\:5p} \\\\ \\ \displaystyle{:\implies\sf\:-\:23p\:-\:69\:=\:3\:-\:5p} \\\\ \\ \displaystyle{:\implies\sf\:-\:23p\:+\:5p\:=\:3\:+\:69} \\ \\ \\\displaystyle{:\implies\sf\:-\:18p\:=\:72} \\ \\\\\displaystyle{:\implies\sf\:p\:=\:-\:\cancel{\dfrac{72}{18}}} \\ \\\\ \displaystyle{:\implies\underline{\boxed{{\sf\:p\:=\:-\:4\:}}}} \red\bigstar \end{gathered}$

$\therefore \underline {\sf{{Hence, the \: value \: of \: p \: is \: \textsf{ \textbf{(-4)}}}}.}$

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