Question

P = {1,3,6,10,15,21........210}. Set builder form​

Answer 1

27 and 29 is the correct answer

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Answer 2

Answer:

{x∈N, such that  $x=\frac{n}{2} (n+1)$ }, n can be natural numbers taken consecutively like 1,2,3,4.....

Step-by-step explanation:

Given-

P = {1,3,6,10,15,21........210}

• The given question represents numbers in a roster form in which the elements or the members of a set are listed in a row inside the curly brackets.
• Set builder form is a short mathematical method to accurately state a specific group of numbers.
• All the elements of a set must satisfy a single property to become a number of that set.
• {x∈N, such that $x=\frac{n}{2} (n+1)$ } is a set builder notation for the given set of numbers in the question.
• n =1, 2,3,4......
• When n=1,

        $x=\frac{1}{2} (1+1)$

        $x=$ $\frac{1}{2}$×$2$

        x=1

• When n=2,

        $x=\frac{2}{2} (2+1)$

        $x=\frac{2}{2}$×$3$

        x=3

• When n=3,

        $x=\frac{3}{2} (3+1)$

        $x=\frac{3}{2}$×$4$

        x=6

Learn more about the set builder form by clicking on the links given below-

https://brainly.in/question/1233994?referrer=searchResults

https://brainly.in/question/16432707?referrer=searchResults