(p+1)³,Expand it, using suitable identities.
Answers
Answered by
71
(a+b)^3= a^3+b^3+3ab (a+b)
= p^3+ 1^3+3*p*1 (p+1)
= p^3+1+3p (p+1)
=p^3+1+3p^2+3p
= p^3+ 1^3+3*p*1 (p+1)
= p^3+1+3p (p+1)
=p^3+1+3p^2+3p
Answered by
99
Solution :
**********************************†*****
We know the algebraic identity ,
( a + b )³ = a³ + 3ab² + 3ab² + b³
******************************************
Now ,
( p + 1 )³
= p³ + 3 × p² × 1 + 3 × p × 1² + 1³
= p³ + 3p² + 3p + 1
••••••
**********************************†*****
We know the algebraic identity ,
( a + b )³ = a³ + 3ab² + 3ab² + b³
******************************************
Now ,
( p + 1 )³
= p³ + 3 × p² × 1 + 3 × p × 1² + 1³
= p³ + 3p² + 3p + 1
••••••
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