Question

(p+1)³ solve using identities ​

Answer 1

We know,

(a + b)³ = a³ + b³ + 3ab(a + b)

Similarly,

(p + 1)³ = p³ + 1³ + 3(p)(1)(p + 1)

$\leadsto$ p³ + 1 + 3p(p + 1)

$\leadsto$ p³ + 1 + 3p² + 3p

$\leadsto$ p³ + 3p² + 3p + 1

Answer 2

(p+1)³

Identity used =a³+b³+3ab(a+b)

= p³+1³+3(p)(1)

=p³+1+3p(p+1)

answer= p³+1+3p²+3p

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