Question

p(1) for p(x) = x³-x²-4 is......

A -4

B 2

C -3

D 4

​

Answer 1

Answer:

$p(x) = {x}^{3} - {x}^{2} - 4 \\ \\ p(1) = (1) ^{3} - {(1)}^{2} - 4 \\ \\ = 1 - 1 - 4 \\ \\ = - 4$

➡ option A = ( - 4 ) ✔✔

# keep smiling ☺

Answer 2

Answer:

x°-4is the correct answer hope you get it no explanation