Math, asked by gitikashekhawat, 22 days ago

p = -1, q = -3, r = 3 then find the value of pq - qr + rp​

Answers

Answered by AoiKanzaki
0

Answer:

⇒x=−3,5

Step-by-step explanation:

Coordinate of point P,Q and R are P(6,-1),Q(1,3) and R(x,8)

Given, PQ=QR

So by distance formula we have,

Distance between two points =  

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

PQ=

(6−1)

2

+(−1−3)

2

=

25+14

=

41

∴PQ

2

=41=QR

2

but, QR

2

=(x−1)

2

+25

41=x

2

+1−2x+25

⇒41=x

2

+1−2x+25

⇒x

2

−2x+26=41

⇒x

2

−2x−15=0

⇒x

2

−5x+3x−15=0

⇒x(x−5)+3(x−5)=0

⇒(x+3)(x−5)=0

Similar questions