Question

(p-1)x^2 -2(p-12) x +2 =0 has equal roots. find p​

Answer 1

Answer:

if roots are equal than b²-4ac = 0

put value ,

b = -2p+24 , C = 2 , a = (p-1)

[(24-2p)² - 4*(P-1) * 2 ] = 0

[(576+4P² -96P) -8P + 8] = 0

[ 4P² -104P + 584 ] = 0

P² - 26P + 146 = 0

Now, we have to find value of P by brahamcharya formula

that will be

P = (26±√92)/2 = 13±√ 23 (Ans.)

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