Question

(p-12)x^2 - 2(p-12)x + 2 = 0 find p

Answer 1

Answer:

Heyaa♡♡

Here is the answer.

For equal roots, D=0,i.e., b2 - 4ac =0

[-2(p - 12)]2 - 4(p - 12) 2= 0

4(p - 12)2 - 8(p - 12) = 0

4(p - 12) (p - 12 - 2) = 0

(p - 12) (p - 14) = 0

p = 12 or p = 14

Rejecting p = 12, as then the given equation will not be true.

We have:-

p = 14

Hope it helped you.