Question

p=₹12000 r=6% t=1 1/2 find compound interest half yearly​

Answer 1

Answer :-

Given -

• Principal = ₹ 12000
• Rate of interest = 6%
• Time = 1.5 years

To Find -

• Compound interest compounded half yearly

Solution -

We know that,

$\sf A = P ( 1 + \frac{\frac{R}{2}}{100})^{2n}$

where

• A is amount
• P is principal
• R is rate of interest
• n is number of years

Substituting the value in formula -

➩ $\sf A = P ( 1 + \frac{\frac{R}{2}}{100})^{2n}$

➩ $\sf A = 12000 ( 1 + \frac{\frac{6}{2}}{100})^{2(1.5)}$

➩ $\sf A = 12000 ( 1 + \frac{3}{100})^3$

➩ $\sf A = 12000 ( \frac{103}{100})^3$

➩ $\sf A = \frac{12\cancel{000} \times 1,092,727}{1000\cancel{000}}$

➩ $\sf A = \frac{13112724}{1000}$

➩ $\sf A = 13,112.724$

We know that,

Compound interest = Amount - Principal

= 13,112.724 - 12000

= 1,112.724

Compound interest = ₹ 1,112.724