Question

P = 19,200 for 11 months at 6.5% interest p.a.
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Answer 1

Answer:

si=1144

p.a=20344

Step-by-step explanation:

$p = 19200 \\ \\ r = 6.5\% \\ \\ n = 11 \: month \\ \\ = > formula \: of \: simple \: interest \\ \\ s.i = \frac{p \times r \times n}{100 } \\ \\ \: \: \: \: \: \: = \frac{19200 \times 6.5 \times 11}{100 \times 12} \\ \\ \: \: \: \: \: \: = \frac{192 \times 6.5 \times 11}{12} \\ \\ \: \: \: \: \: \: = \frac{13728}{12} \\ \\ \: \: \: \: \: \: = 1144 \\ \\ p.a = s.i + p \\ \\ \: \: \: \: \: \: \: = 1144 + 19200 \\ \\ \: \: \: \: \: \: \: = 20344$