Question

P(2/3) for P(y)= 2y3- y2- 13y - 6

Answer 1

$Answer: =\frac{-392}{27}\\\\\\Step-by-step explanation:p(y)=2y^3-y^2-13y-6\\\\\\\\Now\\\\p(\frac{2}{3})\\\\=2(\frac{2}{3})^3-(\frac{2}{3})^2-13(\frac{2}{3})-6\\\\=2(\frac{8}{27})-(\frac{4}{9})-\frac{26}{3}-6\\\\=\frac{16}{27}-(\frac{4}{9})-\frac{26}{3}-6\\\\=\frac{16-12-234-162}{27}\\\\=\frac{16-408}{27}\\\\=\frac{-392}{27}$