Math, asked by jasmeenkaur4151, 1 year ago

p^2-3p+1=0 and p≠ 0 find p^2+1/p^2

Answers

Answered by brunoconti

Answer:

Step-by-step explanation:

yhyy

Attachments:

shadowsabers03: Please where 3 - 1/p should be taken?

shadowsabers03: At the initial stage?

jasmeenkaur4151: its -3p so how did u take -3=1/p

jasmeenkaur4151: -3+1/p**

jasmeenkaur4151: i understood bt can we do tht way??

shadowsabers03: Yes, we can. He divided p^2 - 3p + 1 = 0 by p on both sides to get p - 3 + 1/p = 0.

jasmeenkaur4151: thank u so much sry for bothering uhh

shadowsabers03: You're welcome, it's okay.

brunoconti: thks for answering him. i was way

shadowsabers03: No problem. That's my pleasure. :-)

Answered by shadowsabers03

$\bold{Answer:}$

$\bold{7}$

$\bold{Step}$-$\bold{by}$-$\bold{step\ explanation:}$

$p^2-3p+1=0 \\ \\ p^2+1=3p \\ \\ \frac{p^2+1}{p}=\frac{3p}{3} \\ \\ \frac{p^2}{p} + \frac{1}{p} = \frac{3p}{3} \\ \\ p + \frac{1}{p} = 3$

$(p+\frac{1}{p})^2=3^2 \\ \\ p^2+(\frac{1}{p})^2 + (2 \times p \times \frac{1}{p})=9 \\ \\ p^2+\frac{1}{p^2}+2=9 \\ \\ p^2+\frac{1}{p^2}=9-2 \\ \\ p^2+\frac{1}{p^2}=\bold{7}$

$\therefore\ $Answer is \bold{7}. \\ \\ \\ Hope this may be helpful. \\ \\ Thank you. Have a nice day. :-)$ \\ \\ \\ \\ \\ \#adithyasajeevan \\ \\ \\$

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