P(2,4) q(0,3) r(3,6) and s(5,y) are the vertices of a paralellogram pqrs then value of y is
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Answer:
y = 7
Step-by-step explanation:
midpt of PR= midpt of QS
(2+3/2,4+6/2) = ( 0+5 /2 , y+3/2 )
x - coordinates are equal
equate y- coordinates
10/2 = y+3/2
10 = y+3
y=7
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