Math, asked by AineyAmbey, 9 months ago

(p^2-q^2)^2use identity
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Answers

Answered by pulakmath007
0

\huge\boxed{\underline{\underline{\green{\tt Solution}}}} </p><p>

We are aware of the identity that

 {(x - y)}^{2} =  {x}^{2}  +  {y}^{2}  - 2xy

Using the above mentioned Identity we get

 {( {p}^{2} -  {q}^{2}  )}^{2}  </strong></p><p></p><p><strong>=  {( {p}^{2} )}^{2}  +  {( {q}^{2} )}^{2}  - 2 \times  {p}^{2}  \times  {q}^{2}

=  </strong><strong>{p}^{4}  +  {q}^{4}  - 2 {p}^{2}  {q}^{2}

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