p=2800,r=10,t=3/2 find compound interest
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Given:
(i) Principal value = Rs 2800
(ii) Rate = 10% p.a.
(iii) Time = 3/2 years
To find:
(i) Compound interest amount
Solution:
Assuming interest is compounded yearly, we know that
Amount (A) = P(1 + R/100)ⁿ
where n is the time period, here n = 3/2
So,
A = 2800[(1 + 0.1)^(3/2)]
= 2800[1.3566]
= 3798.48
So, Interest (CI) = A - P
= Rs (3798.48 - 2800)
= Rs 998.48
So, the compound interest is Rs 998.48
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