Question

p^2x^2 +(p^2-q^2)x -q^2=0 using quadratic formula solve equation

Answer 1

Answer:

p²x² +(p²-q²)x -q² =0

b² - 4ac = (p²-q²)² -4 ×p² × (-q²)

(p²)²-2p²q²+(q²)² +4p²q²

(p²)²+2p²q² +(q²)²

(p²+q²)²

-b±√b²-4ac/2a

-(p²-q²)±√(p²+q²)²/2p²

-p²+q²-p²-q²/2p²     or   -p²+q²+p²+q²/2p²

-2p²/2p²           or      2q² /2p²

x= -1            or         x= q²/p²