Question

p^2x^2+(p^2-q^2)x - q^2 solve with correct steps pls.

Answer 1

${p}^{2} {x}^{2} + ( {p}^{2} - {q}^{2} )x - {q}^{2} = 0 \\ {p}^{2} {x}^{2} + {p}^{2} x - {q}^{2} x - {q}^{2} = 0 \\ {p}^{2} x(x + 1) - {q}^{2} (x + 1) = 0 \\ ( {p}^{2} x - {q}^{2} )(x + 1) = 0$
$x = \frac{ {q}^{ 2} }{ {p}^{2} } \: \: \: \: \: or \: \: \: \: \: - 1$
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