Question

P(-3,2) is one end of focal chord PQ of the parabola y^2+4x+4y=0. Then the slope of the normal at Q is

Answer 1

The parabola is (y+2) ^2 = -4(x-1)  

A=  

The point P has t = -2 as (at^2, 2at) gives (-4,4) and on shifting the origin (x-1) = -1  

X = -3 

And (y+2) = 4y = 2 

As PQ is focal chord and t at Q would be +½ (t1,t2 = -1) 

Slope of the normat is –t 

Therefore slope of normal at Q would be -½"

Answer 2

Answer:

The parabola is (y+2) ^2 = -4(x-1)

The point P has t = -2 as (at^2, 2at) gives (-4,4) and on shifting the origin (x-1) = -1

X = -3

And (y+2) = 4y = 2

As PQ is focal chord and t at Q would be +½ (t1,t2 = -1)

Slope of the normat is –t

Therefore slope of normal at Q would be -½

Step-by-step explanation:

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