Question

P
3)
A tent is such that its lower part is cylindrical and upper part is conical. If the
cal part is 2.1m and radius of cylindrical part is 2 m: and slant height of the top is.
area of the canvas used making the tent. Also find the cost of the canvas
nical. If the height of cylindri-
of the top is 2.8 m. Find the
of the canvas used making the tent.Also find the cost of the convas of the tent at the rate of 500 rupees per m square​

Answer 1

Answer:

first we can call part of 2.1radius is *by 2 and -180' then ans 45.58

Answer 2

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From the question, we know that

The diameter = D = 4 m

l = 2.8 m (slant height)

The radius of the cylinder is equal to the radius of the cylinder

So, r = 4/2 = 2 m

Also, we know the height of the cylinder (h) is 2.1 m

So, the required surface area of the given tent = surface area of the cone (the top) + surface area of the cylinder(the base)

= πrl + 2πrh

= πr (l+2h)

Now, substituting the values and solving it we get the value as 44 m^2

∴ The cost of the canvas at the rate of Rs. 500 per m^2 for the tent will be

= Surface area × cost/ m^2

= 44 × 500

So, Rs. 22000 will be the total cost of the canvas

Hope it's Helpful.....:)