p(4,-3) ,q(-2,-2)and r(2,0) then find the equation of the straight line through p and parallel to qr
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2y=x-2
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slope of qr=(y2-y1)/(x2-x1)
=(0-(-2))/(2-(-2))
=2/4=1/2
y-y1=m(x-x1)
y-(-2)=(1/2)(x-(-2))
2y=x-2
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