Question

p (4p^2-16) by 4p (p-2) please solve

Answer 1

Hey
here's your answer !!

p (4p^2-16) ÷ 4p (p-2)
= ( p / 4p ) { ( 4p² -16 ) / (p-2) }
= 1/4 × 4 ( p² - 4 ) / (p - 2 )
= { ( 1/4 × 4 ) (p - 2 ) ( p + 2 ) } / (p - 2 )
= 1 × ( p + 2 )
= ( p + 2 ) . ( answer )

Hope it helps !!

Answer 2

The simplified form of given expression is (p+2).

Step-by-step explanation:

The given expression is

$\dfrac{p(4p^2-16)}{4p(p-2)}$

Taking out common factors from numerator.

$\dfrac{4p(p^2-4)}{4p(p-2)}$

Cancel out common factors.

$\dfrac{p^2-4}{p-2}$

$\dfrac{p^2-2^2}{p-2}$

Using algebraic formula, we get

$\dfrac{(p-2)(p+2)}{p-2}$                    $[\because a^2-b^2=(a-b)(a+b)]$

Cancel out common factors.

$p+2$

Therefore, the simplified form of given expression is (p+2).

#Learn more

Divide. (x^2+2x+1) /(x-2) /(x^2-1) /(x^2-4)

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