P(5,-3) and Q(3,y) are the points of the line segment joining A(7,-2) and B(1,-5). then y equals to
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let AP\PQ = 1\K
K(7)+1(3)
------------- = 5
K+1
7K+3
------- = 5
K+1
7K+3 = 5K=5
2K = 2
K = 1\1
RATIO = 1:1
NOW RATIO = 1:1
1(-2)+1(y)
------------ = -3
2
-6 = -2+y
-4 = y
so y= -4
K(7)+1(3)
------------- = 5
K+1
7K+3
------- = 5
K+1
7K+3 = 5K=5
2K = 2
K = 1\1
RATIO = 1:1
NOW RATIO = 1:1
1(-2)+1(y)
------------ = -3
2
-6 = -2+y
-4 = y
so y= -4
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