Question

P=₹625
R = 4%
T- 2
C| =?
A=?​

Answer 1

Answer:

P=625, R = 4% p.a., T = 2 years.

(ii) P=8000, R = 5% p.a., T = 3 years.

(iii) P=3200, R = 25% p.a., T = 3

Answer 2

Answer :-

• The compound interest is Rs 51.
• The amount is Rs 676.

To find :-

• The amount and compound interest.

Step-by-step explanation :-

• Before finding the compound interest, let's find the amount!!

We know that :-

$\underline{\boxed{\sf Amount = Principal \Bigg(1 + \dfrac{Rate}{100} \Bigg)^{Time}}}$

Here,

• Principal = Rs 625.
• Rate = 4% compounded annually.
• Time = 2 years.

Hence,

$\rm Amount = 625 \Bigg(1 + \dfrac{4}{100} \Bigg)^2$

Reducing 4/100 to it's simplest form,

$\rm Amount = 625 \Bigg(1 + \dfrac{1}{25} \Bigg)^2$

The LCM of 1 and 25 is 25, so adding the fractions using their denominators,

$\rm Amount = 625 \Bigg(\dfrac{1 \times 25 + 1 \times 1}{25} \Bigg)^2$

On simplifying,

$\rm Amount = 625 \Bigg(\dfrac{25 + 1}{25}\Bigg)^2$

Adding 1 to 25,

$\rm Amount =625 \Bigg( \dfrac{26}{25} \Bigg)^2$

Here the power is 2, so removing the brackets and multiplying 26/25 with itself 2 times,

$\rm Amount = 625 \times \dfrac{26}{25} \times \dfrac{26}{25}$

Let's multiply 26/25 with itself first.

$\rm Amount = 625 \times \dfrac{26 \times 26}{25 \times 25}$

On multiplying,

$\rm Amount = \cancel{625} \times \dfrac{676}{\cancel{625}}$

Reducing the numbers,

$\overline{\boxed{\rm Amount = Rs \: 676}}$

----------------------------

• Now, as we know the amount, let's find the compound interest!

We know that :-

$\underline{\boxed{\sf CI = Amount - Principal}}$

Here,

• Amount = Rs 676.
• Principal = Rs 625.

Hence,

$\boxed{\bf CI = 676 - 625}$

$\overline{\boxed{\bf CI = Rs \: 51}}$