Question

p= 6250 a= 7290 r =8% n=?

Answer 1

HEY DEAR HERE IS YOUR ANSWER ✌✌❤❤
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GIVEN :
➡Principal = ₹6250
➡Amount = ₹7290
➡Rate of interest = 8%

TO FIND ? = n

Let the time be t years
According to the question 
Amount =p(1+r/100)^t
6250×(1+8/100)^t=7290
(27/25)^t=7290/6250
(27/25)^t=(27/25)^2 
t=2

hence n = 2

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HOPE IT HELPS U.✌✌
# BE BRAINLY.❤❤
THANKS.❤❤

Answer 2

» REQUARIED Time is n year

» Rate of interest = R =8%

» Principle amount = P = 6250

» amount with compound interest = A = 7290

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$= > a = p \times {(1 + \frac{r}{100}) }^{n} \\ \\ = > 7290 = 6250 \times {(1 + \frac{8}{100}) }^{n} \\ \\ = > 7290 = 6250 \times {( \frac{108}{100}) }^{n} \\ \\ = > \frac{7290}{6250} = {( \frac{27}{25} )}^{n} \\ \\ = > \frac{729}{625} = {( \frac{27}{25}) }^{n} \\ \\ = > {( \frac{27}{25}) }^{2} = {( \frac{27}{25}) }^{n}$
BY COMPARISON , WE GET

$= > n = 2$
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