Question

P=₹6400, Rate=64% ,Pa, S.L = ₹1152 The time =

Answer 1

Answer :-

Given :-

• Principal = ₹6400
• Rate = 64% p.a.
• Simple intetest = ₹1152

To Find :-

• Time, T

Solution :-

Here, we are given principal, rate of interest and simple interest. So by substituting the value in formula of simple interest, we can find time.

Simple interest = P × R × T / 100

→ 1152 = 6400 × 64 × T / 100

→ 1152 = 64 × 64 × T

→ 1152 = 4096 T

→ T = 1152 / 4096

→ T = 9 / 32 years

→ T = 27 / 8 months

Time = 9 / 32 years

Answer 2

Given:-

Principal=₹6400

Rate=64%

S. I (simple interest) =₹1552

Time or n =?

By using Formula:-

SI = $\: \: \: \dfrac{PRT}{100}$

1552=$\: \: \: \dfrac{6400×64×T}{100}$

1552=$\: \: \: \dfrac{64×64×T}{1}$

1552=4096×T

T=$\: \: \: \dfrac{1552}{4096}$

T=$\: \: \: \dfrac{9}{32}$

T=$\: \: \: \dfrac{27}{8}$

T=$\: \: \: \dfrac{9}{32}$ years.