p, 8,11 ......are in a. p then value of p
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Answer:
5
Step-by-step explanation:
as we know that in an arithemitic progression (a.p)
the difference between two consecutive terms is same ,because it is addition of constant terms to the first term to get the second term ,and Soo on ...
now if p , 8 and 11 are in a.p
then 11-8 should be equal to 8-p
therefore 11-8=8-p
p =5
hence you got the value of p
hope it helped you if yes then please thank this answer
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