P (a CosA, a SinA) and, Q(a CosA, -a SinA).......
Find a distance between P and Q using distance formula...
Answers
Answered by
1
(pQ)^2 = (acha A - acosA)^2 + {asinA-(-asinA)}^2
=0^2 + (2asinA)^2
pQ =√(2asinA)^2
pQ= √4a^2sin^2A
pQ= 2asinA
=0^2 + (2asinA)^2
pQ =√(2asinA)^2
pQ= √4a^2sin^2A
pQ= 2asinA
anshikaaaaaa:
ur ans. is wrong i know its ans. bt not its solution
its root2a
plz cheak your question
my ques. is right
Answered by
0
your answer is here in attachment
I hope it will help you
I hope it will help you
Attachments:
ur ans. is also wrong i know its ans bt don't know how to solve this
its ans. is root2
root2a
ok search on Google then or ask teacher
ok
yes i will ask it from my tuition teacher
Similar questions